Optimal. Leaf size=121 \[ -\frac{\left (b^2-2 a c\right ) \tanh ^{-1}\left (\frac{b+2 c (d+e x)^2}{\sqrt{b^2-4 a c}}\right )}{2 a^2 e \sqrt{b^2-4 a c}}+\frac{b \log \left (a+b (d+e x)^2+c (d+e x)^4\right )}{4 a^2 e}-\frac{b \log (d+e x)}{a^2 e}-\frac{1}{2 a e (d+e x)^2} \]
[Out]
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Rubi [A] time = 0.401787, antiderivative size = 121, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 8, integrand size = 30, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.267 \[ -\frac{\left (b^2-2 a c\right ) \tanh ^{-1}\left (\frac{b+2 c (d+e x)^2}{\sqrt{b^2-4 a c}}\right )}{2 a^2 e \sqrt{b^2-4 a c}}+\frac{b \log \left (a+b (d+e x)^2+c (d+e x)^4\right )}{4 a^2 e}-\frac{b \log (d+e x)}{a^2 e}-\frac{1}{2 a e (d+e x)^2} \]
Antiderivative was successfully verified.
[In] Int[1/((d + e*x)^3*(a + b*(d + e*x)^2 + c*(d + e*x)^4)),x]
[Out]
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Rubi in Sympy [A] time = 64.7209, size = 110, normalized size = 0.91 \[ - \frac{1}{2 a e \left (d + e x\right )^{2}} - \frac{b \log{\left (\left (d + e x\right )^{2} \right )}}{2 a^{2} e} + \frac{b \log{\left (a + b \left (d + e x\right )^{2} + c \left (d + e x\right )^{4} \right )}}{4 a^{2} e} - \frac{\left (- 2 a c + b^{2}\right ) \operatorname{atanh}{\left (\frac{b + 2 c \left (d + e x\right )^{2}}{\sqrt{- 4 a c + b^{2}}} \right )}}{2 a^{2} e \sqrt{- 4 a c + b^{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(1/(e*x+d)**3/(a+b*(e*x+d)**2+c*(e*x+d)**4),x)
[Out]
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Mathematica [A] time = 0.249792, size = 154, normalized size = 1.27 \[ \frac{\frac{\left (b \sqrt{b^2-4 a c}-2 a c+b^2\right ) \log \left (-\sqrt{b^2-4 a c}+b+2 c (d+e x)^2\right )}{\sqrt{b^2-4 a c}}+\frac{\left (b \sqrt{b^2-4 a c}+2 a c-b^2\right ) \log \left (\sqrt{b^2-4 a c}+b+2 c (d+e x)^2\right )}{\sqrt{b^2-4 a c}}-\frac{2 a}{(d+e x)^2}-4 b \log (d+e x)}{4 a^2 e} \]
Antiderivative was successfully verified.
[In] Integrate[1/((d + e*x)^3*(a + b*(d + e*x)^2 + c*(d + e*x)^4)),x]
[Out]
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Maple [C] time = 0.018, size = 213, normalized size = 1.8 \[{\frac{1}{2\,{a}^{2}e}\sum _{{\it \_R}={\it RootOf} \left ( c{e}^{4}{{\it \_Z}}^{4}+4\,cd{e}^{3}{{\it \_Z}}^{3}+ \left ( 6\,c{d}^{2}{e}^{2}+b{e}^{2} \right ){{\it \_Z}}^{2}+ \left ( 4\,c{d}^{3}e+2\,bde \right ){\it \_Z}+c{d}^{4}+b{d}^{2}+a \right ) }{\frac{ \left ({{\it \_R}}^{3}bc{e}^{3}+3\,{{\it \_R}}^{2}bcd{e}^{2}+e \left ( 3\,bc{d}^{2}-ac+{b}^{2} \right ){\it \_R}+bc{d}^{3}-acd+{b}^{2}d \right ) \ln \left ( x-{\it \_R} \right ) }{2\,c{e}^{3}{{\it \_R}}^{3}+6\,cd{e}^{2}{{\it \_R}}^{2}+6\,{d}^{2}ec{\it \_R}+2\,c{d}^{3}+be{\it \_R}+bd}}}-{\frac{1}{2\,ae \left ( ex+d \right ) ^{2}}}-{\frac{b\ln \left ( ex+d \right ) }{{a}^{2}e}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(1/(e*x+d)^3/(a+b*(e*x+d)^2+c*(e*x+d)^4),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ -\frac{1}{2 \,{\left (a e^{3} x^{2} + 2 \, a d e^{2} x + a d^{2} e\right )}} + \frac{\int \frac{b c e^{3} x^{3} + 3 \, b c d e^{2} x^{2} + b c d^{3} +{\left (3 \, b c d^{2} + b^{2} - a c\right )} e x +{\left (b^{2} - a c\right )} d}{c e^{4} x^{4} + 4 \, c d e^{3} x^{3} + c d^{4} +{\left (6 \, c d^{2} + b\right )} e^{2} x^{2} + b d^{2} + 2 \,{\left (2 \, c d^{3} + b d\right )} e x + a}\,{d x}}{a^{2}} - \frac{b \log \left (e x + d\right )}{a^{2} e} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/(((e*x + d)^4*c + (e*x + d)^2*b + a)*(e*x + d)^3),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.30177, size = 1, normalized size = 0.01 \[ \left [-\frac{{\left ({\left (b^{2} - 2 \, a c\right )} e^{2} x^{2} + 2 \,{\left (b^{2} - 2 \, a c\right )} d e x +{\left (b^{2} - 2 \, a c\right )} d^{2}\right )} \log \left (\frac{2 \,{\left (b^{2} c - 4 \, a c^{2}\right )} e^{2} x^{2} + 4 \,{\left (b^{2} c - 4 \, a c^{2}\right )} d e x + b^{3} - 4 \, a b c + 2 \,{\left (b^{2} c - 4 \, a c^{2}\right )} d^{2} +{\left (2 \, c^{2} e^{4} x^{4} + 8 \, c^{2} d e^{3} x^{3} + 2 \, c^{2} d^{4} + 2 \,{\left (6 \, c^{2} d^{2} + b c\right )} e^{2} x^{2} + 2 \, b c d^{2} + 4 \,{\left (2 \, c^{2} d^{3} + b c d\right )} e x + b^{2} - 2 \, a c\right )} \sqrt{b^{2} - 4 \, a c}}{c e^{4} x^{4} + 4 \, c d e^{3} x^{3} + c d^{4} +{\left (6 \, c d^{2} + b\right )} e^{2} x^{2} + b d^{2} + 2 \,{\left (2 \, c d^{3} + b d\right )} e x + a}\right ) - \sqrt{b^{2} - 4 \, a c}{\left ({\left (b e^{2} x^{2} + 2 \, b d e x + b d^{2}\right )} \log \left (c e^{4} x^{4} + 4 \, c d e^{3} x^{3} + c d^{4} +{\left (6 \, c d^{2} + b\right )} e^{2} x^{2} + b d^{2} + 2 \,{\left (2 \, c d^{3} + b d\right )} e x + a\right ) - 4 \,{\left (b e^{2} x^{2} + 2 \, b d e x + b d^{2}\right )} \log \left (e x + d\right ) - 2 \, a\right )}}{4 \,{\left (a^{2} e^{3} x^{2} + 2 \, a^{2} d e^{2} x + a^{2} d^{2} e\right )} \sqrt{b^{2} - 4 \, a c}}, \frac{2 \,{\left ({\left (b^{2} - 2 \, a c\right )} e^{2} x^{2} + 2 \,{\left (b^{2} - 2 \, a c\right )} d e x +{\left (b^{2} - 2 \, a c\right )} d^{2}\right )} \arctan \left (-\frac{{\left (2 \, c e^{2} x^{2} + 4 \, c d e x + 2 \, c d^{2} + b\right )} \sqrt{-b^{2} + 4 \, a c}}{b^{2} - 4 \, a c}\right ) + \sqrt{-b^{2} + 4 \, a c}{\left ({\left (b e^{2} x^{2} + 2 \, b d e x + b d^{2}\right )} \log \left (c e^{4} x^{4} + 4 \, c d e^{3} x^{3} + c d^{4} +{\left (6 \, c d^{2} + b\right )} e^{2} x^{2} + b d^{2} + 2 \,{\left (2 \, c d^{3} + b d\right )} e x + a\right ) - 4 \,{\left (b e^{2} x^{2} + 2 \, b d e x + b d^{2}\right )} \log \left (e x + d\right ) - 2 \, a\right )}}{4 \,{\left (a^{2} e^{3} x^{2} + 2 \, a^{2} d e^{2} x + a^{2} d^{2} e\right )} \sqrt{-b^{2} + 4 \, a c}}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/(((e*x + d)^4*c + (e*x + d)^2*b + a)*(e*x + d)^3),x, algorithm="fricas")
[Out]
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Sympy [A] time = 46.3686, size = 464, normalized size = 3.83 \[ \left (\frac{b}{4 a^{2} e} - \frac{\sqrt{- 4 a c + b^{2}} \left (2 a c - b^{2}\right )}{4 a^{2} e \left (4 a c - b^{2}\right )}\right ) \log{\left (\frac{2 d x}{e} + x^{2} + \frac{- 8 a^{3} c e \left (\frac{b}{4 a^{2} e} - \frac{\sqrt{- 4 a c + b^{2}} \left (2 a c - b^{2}\right )}{4 a^{2} e \left (4 a c - b^{2}\right )}\right ) + 2 a^{2} b^{2} e \left (\frac{b}{4 a^{2} e} - \frac{\sqrt{- 4 a c + b^{2}} \left (2 a c - b^{2}\right )}{4 a^{2} e \left (4 a c - b^{2}\right )}\right ) + 3 a b c + 2 a c^{2} d^{2} - b^{3} - b^{2} c d^{2}}{2 a c^{2} e^{2} - b^{2} c e^{2}} \right )} + \left (\frac{b}{4 a^{2} e} + \frac{\sqrt{- 4 a c + b^{2}} \left (2 a c - b^{2}\right )}{4 a^{2} e \left (4 a c - b^{2}\right )}\right ) \log{\left (\frac{2 d x}{e} + x^{2} + \frac{- 8 a^{3} c e \left (\frac{b}{4 a^{2} e} + \frac{\sqrt{- 4 a c + b^{2}} \left (2 a c - b^{2}\right )}{4 a^{2} e \left (4 a c - b^{2}\right )}\right ) + 2 a^{2} b^{2} e \left (\frac{b}{4 a^{2} e} + \frac{\sqrt{- 4 a c + b^{2}} \left (2 a c - b^{2}\right )}{4 a^{2} e \left (4 a c - b^{2}\right )}\right ) + 3 a b c + 2 a c^{2} d^{2} - b^{3} - b^{2} c d^{2}}{2 a c^{2} e^{2} - b^{2} c e^{2}} \right )} - \frac{1}{2 a d^{2} e + 4 a d e^{2} x + 2 a e^{3} x^{2}} - \frac{b \log{\left (\frac{d}{e} + x \right )}}{a^{2} e} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/(e*x+d)**3/(a+b*(e*x+d)**2+c*(e*x+d)**4),x)
[Out]
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GIAC/XCAS [A] time = 0.296676, size = 138, normalized size = 1.14 \[ \frac{b e^{\left (-1\right )}{\rm ln}\left (c + \frac{b}{{\left (x e + d\right )}^{2}} + \frac{a}{{\left (x e + d\right )}^{4}}\right )}{4 \, a^{2}} + \frac{{\left (b^{2} - 2 \, a c\right )} \arctan \left (-\frac{b + \frac{2 \, a}{{\left (x e + d\right )}^{2}}}{\sqrt{-b^{2} + 4 \, a c}}\right ) e^{\left (-1\right )}}{2 \, \sqrt{-b^{2} + 4 \, a c} a^{2}} - \frac{e^{\left (-1\right )}}{2 \,{\left (x e + d\right )}^{2} a} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/(((e*x + d)^4*c + (e*x + d)^2*b + a)*(e*x + d)^3),x, algorithm="giac")
[Out]